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If you are a new C language programmer, you might be wondering how to implement macros similar to the ones shown in this chapter. Macros are not only for assembly language they can be used effectively for high level languages as well. If you are learning to program in C, you may have noticed that there isn t a macro directive as there is in assembly language, but you can use de nes as macros, and using C s ability to concatenate the text on the next line to the current line, you can produce your own multiline macros. The #de ne directive in C is similar to the de ne directive in assembly language; when it is encountered, it replaces the label with the string following the de ne and replaces any parameters with the arguments of the de ne. For example, if you had a circular buffer 20 entries in size and you wanted to increment the indexes to the buffer, you could use the code

buf ndex++; if (19 < buf ndex) buf ndex = 0; // // Increment the buffer index If the index is 20 or greater, reset

If the code were used often and for different index variables, you might want to consider turning it into a single line of code and using it as the basis for a de ne. If you are familiar with C, you would know that you could reduce the three lines above to the single line

Despite being dif cult to read, this single line will increment buf ndex and ensure that it is within range for the 20-element circular buffer. The line then could be turned

into the de ne (which can be used as a macro within C):

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2. Which speech component is developed rst (a) Outline (b) Notes (c) Script (d) Research 3. Which speech component is developed last (a) Outline (b) Notes (c) Script (d) Research 4. Which element of a presentation is not part of an outline (a) Conclusion (b) Transition (c) Notes (d) Thesis 5. Which purpose is not served by creating an outline (a) Helps your thoughts move from one point to another (b) Allows you to keep a logical ow of ideas (c) Is the script you ll use when onstage (d) Helps you feel more comfortable and prepared

#de ne buf nc(indexvar) if (19 < ++indexvar) indexvar = 0;

and each time it is invoked, the code buf nc(buf ndex) would be replaced with the single-line buffer increment and tested to ensure that it is with the index range for the 20-element circular buffer. The problem is that the operation of the de ne is not easily read, and if there were an error in the code, you would not be able to see it easily. What is needed is a way to format the de ne so that the code can be seen easily. Fortunately, C has the backslash character (\) directive, which appends (or concatenate) the next line of text onto the end of the current line. By using this character directive, you can create a multiline de ne (or macro) that is much easier to read and understand, minimizing the opportunity for errors to come into your application. For example, using the backslash character, the buf nc de ne could be rewritten as

#de ne buf nc(indexvar) indexvar++; if (19 < indexvar) indexvar = 0; \ \ \ //

dt Speci ed Address , 0x00D, 0x00A dt J [Address] - Single Step/Jump Over Call Statement , 0x00D dt 0x00A dt G [Address] - Start Application Executing , 0x00D, 0x00A dt I Address - Set the Instruction Pointer , 0x00D, 0x00A dt R - Display the Primary Special Function Registers , 0x00D dt 0x00A dt S RegAddress - Show Contents of 16 Registers Starting at dt the Speci ed Address , 0x00D, 0x00A dt E RegAddress - Load the Register with new Data , 0x00D dt 0x00A dt B [Address] - Toggle the Breakpoint Address , 0x00D, 0x00A dt C - Clear all the Breakpoints , 0x00D, 0x00A dt U [Address] - Display 24 Lines of Instructions , 0x00D dt 0x00A dt + [Address] - Add Instructions to the Program Memory dt 0x00D, 0x00A dt P [E|F] - Program EEPROM or Flash PIC microcontroller MCU , 0x00D dt 0x00A dt V - Verify the Contents of the PIC microcontroller MCU , 0x00D, 0x00A dt 0

For V/F = 5, D/Ii = 0.471, x = 0.0822, dy/d(D/P) = -0.5. For V/F = 2.5, D/F = 0.393, x = 0.196, dy/d(D/F) = -0.2. F o r c o n s t a n t V/P, B = F(1 - z)/(l - z). F o r c o n s t a n t V, B = F[l - ,(a - bF)]. 11.4 Let z1 and z2 be the mole fractions of propane and isobutane, respectively, in the feed; then D = 1f(0.929z1 + 0.912z2 + 0.068). 1 1 . 5 Optimum V/F for z = 0.50 is about 8. 11.6 Optimum V/I; for 2 = 0.60 is about 7; V/F can be programmed with z or with D/b as shown in Fig. 11.20.

and added the two statements:

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